8x^2-19x+32=0

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Solution for 8x^2-19x+32=0 equation: 



8x^2-19x+32=0

a = 8; b = -19; c = +32;
Δ = b2-4ac
Δ = -192-4·8·32
Δ = -663
Delta is less than zero, so there is no solution for the equation

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